# Bar Bending Schedule For RCC Beam

**Calculate The Bar Bending Schedule For RCC Beam**

Today in this article I will explain the bar bending schedule for the RCC beam. the meaning of the bar bending schedule is BBS.in bbs the compete for detail of steel which is used in beam find the length of steel diameter of steel weight of steel.

**What is the RCC Beam?**

A beam, in Structural Engineering terms, is a horizontal member that can be comprised of a number of accouterments (including rebar, wood aluminum) to repel loads generally applied indirectly to the ray axis. Different types of the beam which is used in structural engineering. The most common use of materials is the RCC beam.

**Now we calculate the bar bending schedule for the RCC beam**

**given data **

**Read more**

**Bar bending Schedule of circular column**

**How to Calculate The Bar Bending Schedule For Lintel Beam**

clear span of beam=4.800m

concrete cover top and bottom=25mm

clear cover on ends=40mm

diameter of bottom bar=16mm

diameter of crank bar=16mm

diameter of top bar=12mm

dai meter of strips =8mm

spacing of strrips=150mm

**solution**

**Main bars diameter 16mm**

cutting length of main bar= clear span+2w.t+2bends-2 concrete cover

cutting length of main bar=4800+2(230)+2(2d)-2(40)

cutting length of main bar=4800+460+2(2×16)-80

cutting length of main bar=5260+64-80=5244mm=5.244m

Number of main bar=2

Total length of main bar= length of one bar×number of bar

**Total length of main bar=5.244×2=10.488m**

**Weight of the main bars **

weight of main bar=d²/162.25×total length

weight of main bar=16²/162.25×10.488

weight of main bar=256/162.25×10.488

**weight of main bar=16.548kg=17kg**

**LEARN MORE**

**What Is the Different between the main bar and distribution bar in slab**

**Bar Bending Schedule for Footing**

**Top bars dia 12mm**

Cutting length of top bar= clear span+2w.t+2bends-2 concrete cover

Cutting length of topbar=4800+2(230)+2(2d)-2(40)

Cutting length of top bar=4800+460+2(2×12)-80

Cutting length of top bar=5260+2(24)-80

Cutting length of top bar=5260+48-80=5228mm=5.228m

Number od top bar=2Nos

Total length of top bar=length of one bar × number of bar

**Total length of top bar=5.228× 2=10.456m**

**Weight of Top Bars**

weight of top bar =d²/162.25×total length

weight of top bar =12²/162.25×10.456

**weight of top bar =144/162.25×10456=9.279kg=10kg**

**Crank Bar diameter 16mmH**

Cutting length of crank bar=clear span+2crank length 2w.t+2bends-2 concrete cover

crank length= 0.42d

crank length=0.42(16)=6.72mm

Cutting length of crank bar=4800+2(6.72)+2(230)+2(2d)-2(40)

Cutting length of crank bar=4800+13.44+460+2(2×16)-80=5257.4mm=5.258m

Number of crank bar=2nos

total length of crank bar=length of one bar×number of bar

**Total length of crank bar=5.258×2=10.516m**

**Weight of crank Bar**

Weight of crank bar=d²/162.25×total length

Weight of crank bar=16²/162.25×10.516

**Weight of crank bar=256/162.25×10.516=16.592=17kg**

**Stirrups Diameter 8mm**

Cutting length of stirrups=2(L+w)+3d+2hook-4concrete cover

Cutting length of stirrups=2(500+230)+3(8)+2(9d)-4(25)

Cutting length of stirrups=2(730)+24+2(9×8)-100

Cutting length of stirrups=1460+24+144-100=1528mm=1.528m

Number of stirrups=Total length of beam and wall/spacing+1

Number of stirrups=5260/150+1=36.06=37nos

Total length of stirrups=length of one stirrups×number of stirrups

**Total length of stirrups=1.528×37=56.536m**

**Weight of crank Bar **

weight of crank Bar=d²/162.25×total length

**weight of crank Bar=8²/162.25×56.536=22.300kg=23kg**

Hi ENGR. Numan. How are you? I came across on your website and found it very useful. Thank you!

I would like to ask you regarding the project I am now constructing. I am just a simple foreman and the homeowner decided amd required me to make his project. He is also a professional but not an Engineer. Maybe, he loves reading construction and structural publications?

I have a question about my employer’s design on the beam structure of a G0+1 residential house. The clear span of the RCC beam would be 4200mm. He decided to use 16mm rebars top & bottom (4 pcs) while he used 12mm as crank bars. The spacing of stirrups are standard (4 inches from end of beam to top bend of the crankbars and 6 inches at the middle. Dia. of stirrup is 9mm. He divided the clear span of the beam into 4 equal parts. The upper or top bend is equal to 1050mm from end.

Could you please advise if the metal specs I have stated above won’t create a failure in the future?

Thank you and I pray for your good health.

hi