# How To Calculate The Bar Bending Schedule in Circular Slab

**How To Calculate The Bar Bending Schedule in Circular Slab**

**Calculate the bar bending schedule for circular block the diameter of the block is a pair of 2.5meter**

**given data,**

**Learn more**

# Elements of Road & Carriage Way Details

The main bar is that the diameter of 16mm

The distribution bar is that the diameter of 12mm

Spacing is 200mm and therefore the concrete cowl is 20mm

**Solution**

Spacing is = 200mm

concrete cowl =20mm

The diameter of the block is =2.5m

Step 01

Calculation of the most bar within the center of the block,

Length of main bar =slab diameter -2(concrete cowl on each sides)

Length of main bar= 2500-2(20)

**Length of main bar= 2500-40= 2460mm=2.460m**

Step 2

Calculate the nos’ of facet rebar

Number of bar =radius of slab/spacing

Radius =length /2

Radius = 2.460/2=1.230m

Number of bar =radius /spacing

**Number of bar = 1.230/0.200= 6.15=7no’s**

Now

how to calculate the number of rebar in an exceedingly circular block

Actual variety of 1 sides rebar =Number of main bar – rebar of the middle in block

= 7-1 = 6no’s

Now we discover step by step sides rod

A1=√radius² – spacing² × a pair of

A1= √1.230² – .200² × 2

A1=2.427m

A2 =√radius² –(2×spacing)² × a pair of

A2= √1.230² – 2×.200² x 2

A2=2.3255M

A3= √radius² – 3×spacing² × a pair of

A3 = √1.230² – 3×.200² x 2

A3 =2.147M

A4=√radius² – 4×spacing² × a pair of

A4=√1.230² – 4×.200² x 2

A4= 1.868M

A5= √radius² – 5×spacing² × a pair of

A5=√1.230² – 5×.200² x 2

A5= 1.432M

A6= √radius² – 6×spacing² × a pair of

A6=√1.230² – 6×.200² x 2

A6= 0.540M

We have calculate the worth of

A1= 2.427M

A2= 2.325M

A3= 2.147M

A4=1.868M

A5=1.432M

A6=0.540M

This is one facet length and alternative facet Is same.

A1 TO A6= A7 TO A12

**SO NOW**

main bar total length is = and all bar A1 TO A12

A1+A2+A3+A4+A5+A6+A7+A8+A9+A10+A11+A12

2.427+2.325+2.147+1.868+1.432+.0.50+2.427+2.325+2.147+1.868+1.432+0.540= 21.478

Total length of main bar= one website +other facet =center bar

Total length of main bar= 10.73+10.73+2.460

Total length of main bar= (23.938)M

NOW distribution bar is additionally a similar length however the diameter is totally different.

Main bar total length =distribution bar total length

23.938=23.938

Now calculate the load of main bar 16mm DIA

Main bar =d2/162×23.938

Main bar weight = 16×16/162×23.938

**Main bar weight = in kg 37.828kg =38kg**

Distribution bar weight= d2/162×23.938

Distribution bar weight=12×12/162×23.938

Distribution bar weight=21.27kg=22kg

Nyccc information